PHY301 Assignment No 1 Solution Spring 2022

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PHY301 Assignment No 1 Solution Spring 2022

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Question No 1:
A 20V battery is attached to a circuit containing 2 resistors and a fan having 2 omega resistance.
Part 1: Calculate the source current Is?
Part 2: Determine the voltages V1, V2 and V3?
Part 3: Calculate the power dissipated by each resistor?
Part 4: Determine the power delivered by the source and compare it to the sum of the power levels of part four?

Answer
Part 1:
First, we add a resistor that is in series like V2 and V1 is in series R1 + R2 = 5ohm + 2ohm => 70hm

PHY301 Assignment No 1 Solution Spring 2022

Now,
As we know that V1 is in series with V2
So,
R1 + R2 = 3ohm + 7ohm = 10ohm
So,
PHY301 Assignment No 1 Solution Spring 2022

Now using ohm law for finding source’s current
V3 = 2A * 2 ohm 
V = 1Req
20V = I 10ohm
Is = 20V / 10 ohm
Is = 2A
Part 2:
For V1
V1 = IsR1
V1 = SA * 3ohm
V1 = 6V
SoV2
V2 = IsR2
V2 = 2A * 5ohm
For V3
V3 = IsRs

Part 3:
For P1
P1 = V1Is
P1 = 6V * 2A
P1 = 12W
For P2
P2 = V2Is
P2 = 10V * 2A
P2 = 20W
For P3
P2 = V3Is
P3 = V3Is
P3 = 4V * SA
P3 = 8W

Part 4:
Power Dissipation of source will be:
Ps = Is * Vs
Ps = 2A * 20V
Ps = 40W
SUM and Compare:
Ps = P1 + P2 + P3
Ps = 12W + 20W + 8W
40W = 40W
Question No 2:
Answers the following questions:
Part 1: Why a crow sitting on bare 100KV electric wire not het electric shock?

Answer
Part 1:
Whenever a crow is roosted on a solitary wire of 100KV, its two feet are at a similar electrical potential of 100kV, so the electrons in the wires have no inspiration to go through the crow’s body. No moving electrons implies o electric flow.

Part 2:
Given below are some materials. Mention the conductor, semi-conductor and insulator from them.
Silicon, Silver, Iron, Carbon, Glass, Copper, Rubber.
Answer:

SILICON

Semi-conductor

SILVER

Conductor

IRON

Conductor

CARBON

Insulator

GLASS

Insulator

COPPER

Conductor

RUBBER

Insulator

PHY301 Assignment 1 Solution Spring 2022 in PDF


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